1. 1⅔ =
2. 2¼ =
3. 1 5/7 =
4. 2⅔ =
5. 2⅜ =
6. 25/6 =
7. 37/5 =
8. 19/2 =
9. 51/8 =
10. 30/4 =
RULES :
a. pakai cara & penjelasan
b. tidak menggunakan bhs alien
c. jangan ngasal
d. ngasal? report!
NOTE :
a. untuk no 1-5 diubah menjadi pecahan biasa
b. untuk no 6-10 diubah menjadi pecahan campuran
BIG THANKS FOR U ANSWER! ♡♡
1) 1 2/3 = 1×3+2/3 = 3+2/3 = 5/3
2) 2 1/4 = 2×4+1/4 = 8+1/4 = 9/4
3) 1 5/7 = 1×7+5/7 = 7+5/7 = 12/7
4) 2 2/3 = 2×3+2/3 = 6+2/3 = 8/3
5) 2 3/8 = 2×8+3/8 = 16+3/8 = 19/8
6) 25/6 = 24+1/6 = 24/6 + 1/6 = 4 1/6
cara cpt 25 ÷ 6 = 4 sisa 1, penyebutnya kan 6 = 4 1/6.
7) 37/5 = 35+2/5 = 35/5 + 2/5 = 7 2/5
cara cpt 37 ÷ 5 = 7 sisa 2, penyebutnya kan 5 = 7 2/5.
8) 19/2 = 18+1/2 = 18/2 + 1/2 = 9 1/2
cara cpt 19/2 = 9 sisa 1, penyebutnya kan 2 = 9 1/2.
9) 51/8 = 48+3/8 = 48/8 + 3/8 = 6 3/8
cara cpt 51/8 = 6 sisa 3, penyebutnya kan 8 = 6 3/8.
10) 30/4 = 30÷2/4÷2 = 15/2 = 7 1/2
Jawab:
(1.) = ⁵/₃
(2) = ⁹/₄
(3) = ¹²/₇
(4) = ⁸/₃
(5) = ¹⁹/₈
(6) = 4¹/₆
(7) = 7²/₅
(8) = 9½
(9) = 6⅜
(10) = 7½
Penjelasan:
Pecahan biasa, ᵃ/ₐ = 1, a ≠ 0
(1.) 1⅔ = 1 + ⅔ = ³/₃ + ⅔ = ⁽³⁺²⁾/₃ = ⁵/₃
(2) 2¼ = 2 + ¼ = ⁸/₄ + ¼ = ⁽⁸⁺¹⁾/₄ = ⁹/₄
(3) 1⁵/₇ = 1 + ⁵/₇ = ⁷/₇ + ⁵/₇ = ⁽⁷⁺⁵⁾/₇ = ¹²/₇
(4) 2⅔ = 2 + ⅔ = ⁶/₃ + ⅔ = ⁽⁶⁺²⁾/₃ = ⁸/₃
(5) 2⅜ = 2 + ⅜ = ¹⁶/₈ + ⅜ = ⁽¹⁶⁺³⁾/₈ = ¹⁹/₈
Pecahan campuran [tex]\displaystyle\sf^{(Bilangan\:\:yang\:\:habis\:\:dibagi\:\:penyebut\:+\:bilangan\:\:yg\:\:menghasilkan\:\:pembilang)}/_{Penyebut}[/tex]
(6) ²⁵/₆ = ⁽²⁴⁺¹⁾/₆ = ²⁴/₆ + ¹/₆ = 4 + ¹/₆ = 4¹/₆
(7) ³⁷/₅ = ⁽³⁵⁺²⁾/₅ = ³⁵/₅ + ²/₅ = 7 + ²/₅ = 7²/₅
(8) ¹⁹/₂ = ⁽¹⁸⁺¹⁾/₂ = ¹⁸/₂ + ½ = 9 + ½ = 9½
(9) ⁵¹/₈ = ⁽⁴⁸⁺³⁾/₈ = ⁴⁸/₈ + ⅜ = 6 + ⅜ = 6⅜
(10) ³⁰/₄ = ⁽²⁸⁺²⁾/₄ = ²⁸/₄ + ²/₄ = 7 + ½ = 7½
(xcvi)
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